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Hookah Math


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So tonight me and Akammenzind were smoking some mizo guava and one of our ridiculous conversations ensued. At first it started out at how much smoke has passed through my one hookah, then the cubic yards of smoke that was, then how many times we've filled the room we were smoking based upon that, and then it led to whether or not you'd be able to survive running from one end of hallway to the other with the same cubic dimensions or if you'd die before you did because of oxygen deprivation (you would, by the way).

Anyway, it all came down to one question: how much do you have to smoke to make a ring that encompasses the earth?

I'll spare you the super detailed formulas and simply explain it first. Based on our calculations it takes just under a full year of smoking a bowl a day to create a 1 cubic cm smoke ring around the earth. Here's our math:

So we found that the average human lung capacity is 6 liters of air. This equates to 0.21 cubic feet of 100% pure solid smoke. Since when you exhale the smoke expands and you're never going to see pure solid smoke (although sometimes it seems like it). A good hit will get you roughly a cubic foot of smoke (even though I'm sure we've all had bigger clouds - this is scientific, so we're using averages).

Then we had to figure out the average amount of hits in a bowl. Assuming you are smoking with a friend, the two of you might take 2 hits a minute (once again probably more but this is an average factoring in downtime and the occasional couple minutes that no one is taking a hit). That equates to 4 hits a minute total. If the bowl lasts one hour (again, an average) that is 400 hits per bowl, thus, 400 cubic feet of smoke.

We then took that 400 cubic feet and converted it into cubic yards. Since it is exponential it factored to 27 cubic yards per cubic foot (3x3x3) for a total of 14.8 cubic yards of smoke per bowl. Then we had to convert these cubic yards to cubic centimeters. This comes out to 11,315,412 cubic centimeters. Then we must convert these centimeters to kilometers. It came out to a whopping 113 kilometers... for one bowl.Already that's a 113 kilometer ring, but multiply that by 365 (one bowl for every day of the year) and you get 41,245km. The circumfrence of the earth? 40,075km.

So... if you and a friend smoked a bowl a day for a year, taking an average of a combined 4 hits per minutes, you produce enough smoke to make a 1 cubic centimeter ring that encompasses the earth (and then some) at the equator.

This is probably the best thing I've ever used math for. I'm interested in seeing some other equasions people come up with. _sheesha2__by_Majunka_aurore.gif
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QUOTE (mattarios2 @ Oct 31 2009, 11:01 AM) <{POST_SNAPBACK}>
so i've circled the earth like 6-7 times, heh, good discussion!


Lol yeah, that's a lot of smoking!

Kinda was hoping more people would get into the math of it and come up with other fun scenarios like how many bowls it'd take to reach the moon, mars, the sun, etc sad.gif
Guess I'll have to do that another time and post my results tongue.gif
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i started to make a post like that but decided not to because i didnt want to be "that guy".

here it goes..

So, if your math is correct your saying that a person that is determined to do this taking and average of 4 puffs per minute and smoking for 16 hours per day can make a smoke ring to go around earth in about 23 days time?

what about a hookah bar that is open? if they are open 8 hours per day (from 4-12) and on average they get about 25 people in per day smoking for an hour each then they would have enough smoke settling in the hookah bar to make a 1 cm smoke ring around the world in a little over 2 weeks? what if they get 50 people in per day? every week there is enough smoke produced in one hookah lounge to make a 1 cm smoke ring around the world?

kinda crazy
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QUOTE (Canon @ Oct 31 2009, 12:32 PM) <{POST_SNAPBACK}>
i started to make a post like that but decided not to because i didnt want to be "that guy".

here it goes..

So, if your math is correct your saying that a person that is determined to do this taking and average of 4 puffs per minute and smoking for 16 hours per day can make a smoke ring to go around earth in about 23 days time?

what about a hookah bar that is open? if they are open 8 hours per day (from 4-12) and on average they get about 25 people in per day smoking for an hour each then they would have enough smoke settling in the hookah bar to make a 1 cm smoke ring around the world in a little over 2 weeks? what if they get 50 people in per day? every week there is enough smoke produced in one hookah lounge to make a 1 cm smoke ring around the world?

kinda crazy



We could be sending up smoke rings to FAAAR away galaxies via Hookah puffing...please, everyone, start learning to smoke Heart Rings so our alien overlords know we mean peace!
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QUOTE (jordanneff @ Nov 1 2009, 03:10 AM) <{POST_SNAPBACK}>
QUOTE (mattarios2 @ Oct 31 2009, 11:01 AM) <{POST_SNAPBACK}>
so i've circled the earth like 6-7 times, heh, good discussion!


Lol yeah, that's a lot of smoking!

Kinda was hoping more people would get into the math of it and come up with other fun scenarios like how many bowls it'd take to reach the moon, mars, the sun, etc sad.gif
Guess I'll have to do that another time and post my results tongue.gif



1,295,750 bowls to the sun (3,550 years) and 3402 bowls to the moon (9.3 years)
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Your math and assumptions are faulty. However, its an interesting thought experiment.

First off, I was under the impression that the average lung capacity for the average human lung capacity is 5L, and if the average lung full is .21 ft3, you couldn't get 1 ft3 from one hit. That would be five hits. Thats assuming that 100% of your lungs are full. I would guess its 10-20%, personally. Your math is faulty when you guess that there are 4 hits/minute and the average bowl lasts one hour. There are only 60 minutes in an hour, not 100. Unless you're using that old-fashioned metric time. Therefore, there would be 240 hits/bowl. If, then we take a 20% lung load of 5L lungs (mine are 7.5L and are the largest several doctors have ever seen outside of deep sea divers), that would be .035 ft3/hit. Even if lungs are 6L on average, thats still ~18% capacity...thats still a good guess. Times 240 hits/bowl (assuming constant smoke generation). Thats 8.4 ft3 /bowl. or .31 yd3/bowl. Why you would convert to yd3 to convert to cm3, I don't know. smile.gif There are 61.02 in3/L (a 302 in3 car engine is 5L). Therefore, .061 in3/ml= .061 in3/cm3. 8.4 ft3/bowl translates to 14515 in3/bowl, dividing by 61.02 in3/L (=61.02 in3/dm3) =237.9 dm3= [dividing by 10000^3....10000 dm in 1Km] 2.38 x10^-10 Km3.

[There are 1x10-15 Km3/cm3. From your math 1.13x10-8 Km3/bowl...you forgot some conversions somewhere...there are 100000^3 cm3/Km3 you only divided by 100000 once, not thrice]. because 11,315,000 cm3 divided by 100000 is "113 Km". You need to divide by 1,000,000,000,000,000. Thats 1.13x10^-8 Km3, you would have to assume a cross-sectional area of the smoke ring of 1x10^-10 Km2...or 1 cm2...either 1 cm x 1cm square or the linearly larger circular cross-sectional area.

Going back to my math, if we assume the smoke ring has a very tiny 1 cm2 cross-sectional area, like you assumed, I would estimate a smoke ring of a length of 2.38 Km. The circumference...of the Earth is, equatorially (As opposed to meridianially) is 40,000 Km (actually, they're both about 40,000 Km). 868.7 Km for one years smoking (2.38 Km x 365 days.year)...it would take you approximately 46 Years to encircle the Earth once.

Obviously, we haven't taken into account error propagation or significant figures. I used my cell phone for a lot of the math, which actually sucks. sad.gif.

Fun project! Now calculate how many years it would take to encircle the Sun or Jupiter, neglecting magnetic or particle disruption. That should be shocking!
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QUOTE (Sonthert @ Oct 31 2009, 06:55 PM) <{POST_SNAPBACK}>
Your math and assumptions are faulty. However, its an interesting thought experiment.

First off, I was under the impression that the average lung capacity for the average human lung capacity is 5L, and if the average lung full is .21 ft3, you couldn't get 1 ft3 from one hit. That would be five hits. Thats assuming that 100% of your lungs are full. I would guess its 10-20%, personally. Your math is faulty when you guess that there are 4 hits/minute and the average bowl lasts one hour. There are only 60 minutes in an hour, not 100. Unless you're using that old-fashioned metric time. Therefore, there would be 240 hits/bowl. If, then we take a 20% lung load of 5L lungs (mine are 7.5L and are the largest several doctors have ever seen outside of deep sea divers), that would be .035 ft3/hit. Even if lungs are 6L on average, thats still ~18% capacity...thats still a good guess. Times 240 hits/bowl (assuming constant smoke generation). Thats 8.4 ft3 /bowl. or .31 yd3/bowl. Why you would convert to yd3 to convert to cm3, I don't know. smile.gif There are 61.02 in3/L (a 302 in3 car engine is 5L). Therefore, .061 in3/ml= .061 in3/cm3. 8.4 ft3/bowl translates to 14515 in3/bowl, dividing by 61.02 in3/L (=61.02 in3/dm3) =237.9 dm3= [dividing by 10000^3....10000 dm in 1Km] 2.38 x10^-10 Km3.

[There are 1x10-15 Km3/cm3. From your math 1.13x10-8 Km3/bowl...you forgot some conversions somewhere...there are 100000^3 cm3/Km3 you only divided by 100000 once, not thrice]. because 11,315,000 cm3 divided by 100000 is "113 Km". You need to divide by 1,000,000,000,000,000. Thats 1.13x10^-8 Km3, you would have to assume a cross-sectional area of the smoke ring of 1x10^-10 Km2...or 1 cm2...either 1 cm x 1cm square or the linearly larger circular cross-sectional area.

Going back to my math, if we assume the smoke ring has a very tiny 1 cm2 cross-sectional area, like you assumed, I would estimate a smoke ring of a length of 2.38 Km. The circumference...of the Earth is, equatorially (As opposed to meridianially) is 40,000 Km (actually, they're both about 40,000 Km). 868.7 Km for one years smoking (2.38 Km x 365 days.year)...it would take you approximately 46 Years to encircle the Earth once.

Obviously, we haven't taken into account error propagation or significant figures. I used my cell phone for a lot of the math, which actually sucks. sad.gif .

Fun project! Now calculate how many years it would take to encircle the Sun or Jupiter, neglecting magnetic or particle disruption. That should be shocking!


Thanks Eric....party pooper.
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QUOTE (Sonthert @ Nov 1 2009, 10:55 AM) <{POST_SNAPBACK}>
Your math and assumptions are faulty. However, its an interesting thought experiment.

First off,[bunch of stuff no one understands]

Obviously, we haven't taken into account error propagation or significant figures. I used my cell phone for a lot of the math, which actually sucks. sad.gif.

Fun project! Now calculate how many years it would take to encircle the Sun or Jupiter, neglecting magnetic or particle disruption. That should be shocking!



this is how you made me feel reading that eric

facepalm.gif getout.gif ban.gif smiley-angry021.gif dash1.gif lol_hitting.gif
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QUOTE (Sonthert @ Nov 1 2009, 10:55 AM) <{POST_SNAPBACK}>
Fun project! Now calculate how many years it would take to encircle the Sun or Jupiter, neglecting magnetic or particle disruption. That should be shocking!

Assuming your math is correct it would take APX 517 years for Jupiter and 5,022 years for the sun.
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